Question

calcule
$\frac{2 { - }^{2} { -}2^{ -3} }{2 {}^{2} }$
​

Answer 1

$\frac{2^{-2}-2^{-3}}{2^2} =\frac{\big(\frac{1}{2}\big)^2-\big(\frac{1}{2}\big)^3 }{4} =\frac{\frac{1}{4}-\frac{1}{8}}{4} =\frac{\frac{2}{8}-\frac{1}{8}}{4} =\frac{\frac{2-1}{8}}{4} =\frac{\frac{1}{8}}{4} =\frac{1}{8} \cdot\frac{1}{4} =\frac{1\cdot1}{8\cdot4} =\frac{1}{32}$