Question

calcule: $3 \pi (2 \pi ) ^{2} +5 \pi ^{2} +5 \pi -(3 \pi ) ^{3} + \pi ^{2} -4.$

Answer 1

$3\pi(2\pi)^2+5\pi^2+5\pi-(3\pi)^3+\pi^2-4=\\ \\ 12\pi^3+5\pi^2+5\pi-27\pi^3+\pi^2-4=\\ \\ -15\pi^3+6\pi^2+5\pi-4$

Answer 2

Ola Junior

3π*(2π)² + 5π² + 5π - (3π)³ + π²  - 4 = 

12π³ + 5π² + 5π - 27π³ + π²  - 4  =

-15π³ + 6π² + 5π - 4 

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