Question

calcule sen x,cos x e tg x,do triângulo abaixo ​

Answer 1

Cateto oposto→9

Cateto adjacente→12

hipotenusa →15

$\mathsf{seno=\dfrac{cateto~oposto}{hipotenusa}}\\\mathsf{sen(x)=\dfrac{9}{15}}$

$\mathsf{cosseno=\dfrac{cateto~adjacente}{hipotenusa}}\\\mathsf{cos(x)=\dfrac{12}{15}}$

$\mathsf{tangente=\dfrac{cateto~oposto}{cateto~adjacente}}\\\mathsf{tg(x)=\dfrac{9}{12}}$