Question

Calcule sen α, cos α e tg α.

Answer 1

Explicação passo-a-passo:

• $\sf sen~\alpha=\dfrac{cateto~oposto}{hipotenusa}$

$\sf sen~\alpha=\dfrac{1}{\sqrt{5}}$

$\sf sen~\alpha=\dfrac{1}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}$

$\sf \red{sen~\alpha=\dfrac{\sqrt{5}}{5}}$

• $\sf cos~\alpha=\dfrac{cateto~adjacente}{hipotenusa}$

$\sf cos~\alpha=\dfrac{2}{\sqrt{5}}$

$\sf cos~\alpha=\dfrac{2}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}$

$\sf \red{cos~\alpha=\dfrac{2\sqrt{5}}{5}}$

• $\sf tg~\alpha=\dfrac{cateto~oposto}{cateto~adjacente}$

$\sf \red{tg~\alpha=\dfrac{1}{2}}$