Question

Calcule Se f(x) = 1/3x^3 + 1/2x^2-2x;

Sendo x=0; x=-2; x=10; x=-1

Answer 1

Olá,

f(x) = (1/3)x³+(1/2)x²-2x
f(0) = (1/3)*0+(1/2)*0-2*0=0
f(-2) = (1/3)*(-8)+(1/2)*4-2*(-2)=10/3=3,33333...
f(10) = (1/3)*1000+(1/2)*100-2*10=1090/3=343,33333...
f(-1) = (1/3)*(-1)+(1/2)*1-2*(-1)=13/6=2,16666...

Atenciosamente,