Question

calcule reduzindo os termos : a) (x+3)²+x²-10 B) ( x - 1) . (x + 5) - 3 . ( x² - 3 ) C ) (3 y+2 )²+ ( y - 2) . ( y + 2 ) D)( 2 xy + 5 ) . ( xy -1) - 3x²y² - xy -5 E) (a + b)² + ( a + b ) . ( a -b )

Answer 1

a) (x+3)^2+x^2-10

x^2+2.x.3+3^2= x^2+6x+9

x^2+6x+9+x^2-10=

2x^2+6x-1