Question

calcule: radical

a) (√3+√2)²


b) (1-√7)²


c)(4√2+5).(4√2-5)


d)(2+√10)²


e)(√11+√7).(√11-√7)


f) (3√3+√2)²

Answer 1

a) (√3+√2)² =  3 + 2√3√2 + 2 ==> 5 + 2√6


b) (1-√7)² =  1 - 2√7 + 7 ==> 8 - 2√7


c)(4√2+5).(4√2-5) = 16.2 - 25 ==> 32 - 25 ==> 7


d)(2+√10)² = 4 + 2.2√10 + 10 ==> 14 + 4√10


e)(√11+√7).(√11-√7) = 121 - 7 ==. 114


f) (3√3+√2)² = 9.3 + 2.3√3√2 + 2 ==. 27+2 +6√6 ==> 29 +6√6