calcule ( produtos notáveis )
a)(2x+1/2)²=
b)( x/2 +y/2)²=
c) (3y+3x)²=
por favor me ajudem
Soluções para a tarefa
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2
A)
![(2x + \frac{1}{2} ) ^{2} = (2x + \frac{1}{2} )(2x + \frac{1}{2} ) \\ 4 {x}^{2} + (2x \times \frac{1}{2}) + ( \frac{1}{2} \times 2x) + \frac{1}{4} (2x + \frac{1}{2} ) ^{2} = (2x + \frac{1}{2} )(2x + \frac{1}{2} ) \\ 4 {x}^{2} + (2x \times \frac{1}{2}) + ( \frac{1}{2} \times 2x) + \frac{1}{4}](https://tex.z-dn.net/?f=%282x+%2B+%5Cfrac%7B1%7D%7B2%7D+%29+%5E%7B2%7D+%3D+%282x+%2B+%5Cfrac%7B1%7D%7B2%7D+%29%282x+%2B+%5Cfrac%7B1%7D%7B2%7D+%29+%5C%5C+4+%7Bx%7D%5E%7B2%7D+%2B+%282x+%5Ctimes+%5Cfrac%7B1%7D%7B2%7D%29+%2B+%28+%5Cfrac%7B1%7D%7B2%7D+%5Ctimes+2x%29+%2B+%5Cfrac%7B1%7D%7B4%7D+)
Temos que
![2x \times \frac{1}{2} = \frac{2x}{2} = x 2x \times \frac{1}{2} = \frac{2x}{2} = x](https://tex.z-dn.net/?f=2x+%5Ctimes+%5Cfrac%7B1%7D%7B2%7D+%3D+%5Cfrac%7B2x%7D%7B2%7D+%3D+x)
Então
![4 {x}^{2} + x + x + \frac{1}{4} \\ 4 {x}^{2} + 2x + \frac{1}{4} 4 {x}^{2} + x + x + \frac{1}{4} \\ 4 {x}^{2} + 2x + \frac{1}{4}](https://tex.z-dn.net/?f=4+%7Bx%7D%5E%7B2%7D+%2B+x+%2B+x+%2B+%5Cfrac%7B1%7D%7B4%7D+%5C%5C+4+%7Bx%7D%5E%7B2%7D+%2B+2x+%2B+%5Cfrac%7B1%7D%7B4%7D+)
B)
![( \frac{x}{2} + \frac{y}{2} )^{2} =( \frac{x}{2} + \frac{y}{2} )( \frac{x}{2} + \frac{y}{2} ) \\ \frac{x}{2} \times \frac{x}{2} + \frac{x}{2} \times \frac{y}{2} + \frac{y}{2} \times \frac{x}{2} + \frac{y}{2} \times \frac{y}{2} ( \frac{x}{2} + \frac{y}{2} )^{2} =( \frac{x}{2} + \frac{y}{2} )( \frac{x}{2} + \frac{y}{2} ) \\ \frac{x}{2} \times \frac{x}{2} + \frac{x}{2} \times \frac{y}{2} + \frac{y}{2} \times \frac{x}{2} + \frac{y}{2} \times \frac{y}{2}](https://tex.z-dn.net/?f=%28+%5Cfrac%7Bx%7D%7B2%7D+%2B+%5Cfrac%7By%7D%7B2%7D+%29%5E%7B2%7D+%3D%28+%5Cfrac%7Bx%7D%7B2%7D+%2B+%5Cfrac%7By%7D%7B2%7D+%29%28+%5Cfrac%7Bx%7D%7B2%7D+%2B+%5Cfrac%7By%7D%7B2%7D+%29+%5C%5C+%5Cfrac%7Bx%7D%7B2%7D+%5Ctimes+%5Cfrac%7Bx%7D%7B2%7D+%2B+%5Cfrac%7Bx%7D%7B2%7D+%5Ctimes+%5Cfrac%7By%7D%7B2%7D+%2B+%5Cfrac%7By%7D%7B2%7D+%5Ctimes+%5Cfrac%7Bx%7D%7B2%7D+%2B+%5Cfrac%7By%7D%7B2%7D+%5Ctimes+%5Cfrac%7By%7D%7B2%7D+)
Temos que
![\frac{x}{2} \times \frac{x}{2} = \frac{ {x}^{2} }{4} \frac{x}{2} \times \frac{x}{2} = \frac{ {x}^{2} }{4}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx%7D%7B2%7D+%5Ctimes+%5Cfrac%7Bx%7D%7B2%7D+%3D+%5Cfrac%7B+%7Bx%7D%5E%7B2%7D+%7D%7B4%7D+)
![\frac{x}{2} \times \frac{y}{2} = \frac{xy}{4} \frac{x}{2} \times \frac{y}{2} = \frac{xy}{4}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx%7D%7B2%7D+%5Ctimes+%5Cfrac%7By%7D%7B2%7D+%3D+%5Cfrac%7Bxy%7D%7B4%7D+)
![\frac{y}{2} \times \frac{y}{2} = \frac{ {y}^{2} }{4} \frac{y}{2} \times \frac{y}{2} = \frac{ {y}^{2} }{4}](https://tex.z-dn.net/?f=+%5Cfrac%7By%7D%7B2%7D+%5Ctimes+%5Cfrac%7By%7D%7B2%7D+%3D+%5Cfrac%7B+%7By%7D%5E%7B2%7D+%7D%7B4%7D+)
Então
![\frac{ {x}^{2} }{4} + \frac{xy}{4} + \frac{xy}{4} + \frac{ {y}^{2} }{4 } = \\ \frac{ {x}^{2} }{4} + \frac{xy}{2} + \frac{ {y}^{2} }{4} \frac{ {x}^{2} }{4} + \frac{xy}{4} + \frac{xy}{4} + \frac{ {y}^{2} }{4 } = \\ \frac{ {x}^{2} }{4} + \frac{xy}{2} + \frac{ {y}^{2} }{4}](https://tex.z-dn.net/?f=+%5Cfrac%7B+%7Bx%7D%5E%7B2%7D+%7D%7B4%7D+%2B+%5Cfrac%7Bxy%7D%7B4%7D+%2B+%5Cfrac%7Bxy%7D%7B4%7D+%2B+%5Cfrac%7B+%7By%7D%5E%7B2%7D+%7D%7B4+%7D+%3D+%5C%5C+%5Cfrac%7B+%7Bx%7D%5E%7B2%7D+%7D%7B4%7D+%2B+%5Cfrac%7Bxy%7D%7B2%7D+%2B+%5Cfrac%7B+%7By%7D%5E%7B2%7D+%7D%7B4%7D+)
C)
Temos que
Então
B)
Temos que
Então
C)
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