Question

calcule ponto medio e os comprimentos das medidas de um triangulo cujo vertices sao os pontos A(2,6) B (4,2) C (5,9)

Answer 1

Olá Caroline 

pontos médios

Mx = (Ax + Bx)/2
Mx = (2 + 4)/2 = 6/2 = 3

My = (Ay + By)/2 
My = (6 + 2)/2 = 8/2 = 4

Nx = (Bx + Cx)/2
Nx = (4 + 5)/2 = 9/2

Ny = (By + Cy)/2 
Ny = (2 + 9)/2 = 11/2

Px = (Ax + Cx)/2
Px = (2 + 5)/2 = 7/2

Py = (Ay + Cy)/2
Py = (6 + 9)/2 = 15/2

os lados

AB² = (Ax - Bx)² + (Ay - By)²
AB² = (2 - 4)² + (6 - 2)² 
AB² = 2² + 4² = 4 + 16 = 20

AC² = (Ax - Cx)² + (Ay - Cy)²
AC² = (2 - 5)² + (6 - 9)²
AC² = 3² + 3² = 9 + 9 = 18

BC² = (Bx - Cx)² + (By - Cy)²
BC² = (4 - 5)² + (2 - 9)²
BC² = 1² + 7² = 1 + 49 = 50

AB = 2√5
AC = 3√2
BC = 5√2 

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