Question

calcule os zeros de cada função

a) F (x) = 3x+18

b) F (x) = x2+9x+20

c) F (x) = x2+3x-10​​

Answer 1

Explicação passo-a-passo:

a) 0 = 3x + 18

- 3x = 18

x = 18/-3

x= - 6

b) x² +9x +20=0

∆= 9² - 4.1.20

∆= 81 - 80

∆= 1

x= - 9 ±√1/2.1

x= - 9 ±1/2

x1= -9+1/2= -8/2= -4

x2= -9-1/2= - 10/2= -5

S = { -4, -5}

c) x² +3x - 10=0

∆= 3² - 4.1.(-10)

∆= 9 + 40

∆= 49

x= - 3 ±√49/2.1

x= - 3 ±7/2

x1= -3+7/2= 4/2= 2

x2= -3-7/2= -10/2= -5

S = { -5, 2}