Question

calcule os zeros das seguintes funções.(fx)=-x2-x+12

Answer 1

-x2-x+12=0
1+48=49
1+7/-2=-4
1-7/-2=3
logo resposta (-4,3)

Answer 2

$-x^2-x+12=0 \\ \Delta=(-1)^2-4.(-1).12=1+48=49 \\ x=\frac{1+-\sqrt{49}}{2.(-1)}=\frac{1+-7}{-2} \\ \\ x_1=\frac{-6}{-2}=3 \\ \\ x_2=\frac{8}{-2}=-4$