Question

calcule os valores reais de x e y para que a igualdade se verifique : (3x² + 4xyi) - (x² + yi) = 8 + 3i

Answer 1

$(3x^2+4xyi)-(x^2+yi)=8+3i\\ \\ 3x^2+4xyi-x^2-yi=8+3i\\ \\ (3x^2-2x^2)+(4xy-y)i\\ \\ x^2+(4xy-y)i=8+3i\\ \\ x^2=8\Rightarrow x=2\sqrt2\\ \\ 4xy-y=3\\ \\ 8\sqrt2y-y=3\\ \\ (8\sqrt2-1)y=3\\ \\ y=\frac{3}{8\sqrt2-1}$