Question

Calcule os valores de c,r e y do triângulo

Answer 1

Resposta:

Explicação passo-a-passo:

$r^{2} = (3\sqrt{2}) ^{2} + (\sqrt{7}) ^{2}$

$r^{2} = 9\sqrt{4} + \sqrt{49}$

$r^{2} = 9.2 + 7$

$r^{2} = 18+7$

$r^{2} = 25$

r = 5

===================================================================

$(3\sqrt{2}) ^{2} = 5.y$

$9\sqrt{4} = 5.y$

9.2 = 5.y

18 = 5.y

y = $\frac{18}{5}$

y = 3,6

==================================================================

x = 5 - 3,6

x = 1,4

=================================================================

$c^{2} = 3,6 . 1,4\\c^{2} = 5,04\\c = 2,24$