Question

Calcule os sistemas

3x+2y+3z=0
x+y+z=1
2x-3y+=5

Answer 1

x+y+z=1(-3)
3x+2y+3z=0
Fica:
-3x-3y-3z=-3
3x+2y+3z=0
-y =-3
y=3"
2x-3(3)=5
x=7"
3(7)+2(3)+3z=0
z=-27/3
z=-9" S{(7,3,-9)}