Question

Calcule os seguintes quocientes: a)-4-i/8-i

Answer 1

$\frac{-4-i}{8-i} =\frac{-4-i}{8-i}. \frac{8+i}{8+i} = \frac{-32-4i-8i-i^{2}}{8^{2}-i^{2}} \\ \\ \frac{-32-12i-(-1)}{64-(-1)} = \frac{-32-12i+1}{64+1} = \frac{-31-12i}{65}$

Espero ter ajudado.

Answer 2

-4-i/8-i  ∴

-4-i /  .  8+i
8-i       8+i

-32-8i-4i-i^2/64-i^2

-32-12i+1/65

-31-12i/65