Question

calcule os seguintes logaritmos usando a definição geral.​

Answer 1

Resposta:

$a)\\ \log_{25}625=2\\ \\\log_{25}625=x\\ \\ 25^x=625\\ \\ 5^{2x}=5^4\\ \\ 2x=4\\ x=4\div2\\ x=2$

$b)\\ \log_{{1\over4}}\sqrt[3]{16} =-{2\over3}\\ \\ ({1\over4})^x=\sqrt[3]{16} \\ \\ 4^{-x}=\sqrt[3]{4^2} \\ \\ 4^{-x}=4^{{2\over3}}\\ \\ -x={2\over3}\\ \\ x=-{2\over3}$