Question

calcule os produtos notáveis: me ajudem e pra amanhã por favor me ajudem por favor​

Answer 1

Olá!

h) (2x - b)²

(2x)² - 2·2x·b + b²

4x² - 4xb + b²

i) (5x² - 1)²

(5x²)² - 2·5x²·1  + 1²

25x⁴ - 10x² + 1

j) (x² - 1)²

(x²)² - 2·x²·1 + 1²

x⁴ - 2x² + 1

l) (9x² - 1)²

(9x²)² - 2·9x²·1 + 1²

81x⁴ - 18x² + 1

m) (x³ - 2)²

(x³)² - 2·x³·2 + 2²

x⁶ - 4x³ + 4

n) (3x² - y²)·(3x² + y²)

9x⁴ + 3x²y² - 3x²y² - y⁴

9x⁴ - y⁴

o) (x + 1/2)·(x - 1/2)

x² - x/2 + x/2 - 1/4

x² - 1/4

p) (x - 2/3)·(x + 2/3)

x² + 2x/3 - 2x/3 - 4/9

x² - 4/9

q) (x/4 + 2/3)·(x/4 - 2/3)

x²/16 - 2x/12 + 2x/12 - 4/9

x²/16 - 4/9

r) (x + 3)·(x - 3)

x² - 3x + 3x - 9

x² - 9

s) (2x + 5)·(2x - 5)

4x² - 10x + 10x - 25

4x² - 25

t) (3x - 2)·(3x + 2)

9x² + 6x - 6x - 4

9x² - 4

:)

Answer 2

Oie, Td Bom?!

h)

$= (2x - b) {}^{2}$

$= (2x) {}^{2} - 2 \: . \: 2xb + b {}^{2}$

$= 4x {}^{2} - 4bx + b {}^{2}$

i)

$= (5x {}^{2} - 1) {}^{2}$

$= (5x {}^{2} ) {}^{2} - 2 \: . \: 5x {}^{2} \: . \: 1 + 1 {}^{2}$

$= 25x {}^{4} - 10x {}^{2} + 1$

j)

$= (x {}^{2} - 1) {}^{2}$

$= (x {}^{2} ) {}^{2} - 2x {}^{2} \: . \: 1 + 1 {}^{2}$

$= x {}^{4} - 2x {}^{2} + 1$

l)

$= (9x {}^{2} - 1) {}^{2}$

$= (9x {}^{2} ) {}^{2} - 2 \: . \: 9x {}^{2} \: . \: 1 + 1 {}^{2}$

$= 81x {}^{4} - 18x {}^{2} + 1$

m)

$= (x {}^{3} - 2) {}^{2}$

$= (x {}^{3} ) {}^{2} - 2x {}^{3} \: . \: 2 + 2 {}^{2}$

$= x {}^{6} - 4x {}^{3} + 4$

n)

$= (3x {}^{2} - y {}^{2} ) \: . \: (3x {}^{2} + y {}^{2} )$

$= (3x {}^{2} ) {}^{2} - (y {}^{2} ) {}^{2}$

$= 9x {}^{4} - y {}^{4}$

o)

$= (x + \frac{1}{2} ) \: . \: (x - \frac{1}{2} )$

$= x {}^{2} - ( \frac{1}{2} ) {}^{2}$

$= x {}^{2} - \frac{1}{4}$

p)

$= (x - \frac{2}{3} ) \: . \: (x + \frac{2}{3} )$

$= x {}^{2} - ( \frac{2}{3} ) {}^{2}$

$= x {}^{2} - \frac{4}{9}$

q)

$= ( \frac{x}{4} + \frac{2}{3} ) \: . \: ( \frac{x}{4} - \frac{2}{3} )$

$= ( \frac{x}{4} ) {}^{2} - ( \frac{2}{3} ) {}^{2}$

$= \frac{x {}^{2} }{16} - \frac{4}{9}$

r)

$= (x + 3) \: . \: (x - 3)$

$= x {}^{2} - 3 {}^{2}$

$= x {}^{2} - 9$

s)

$= (2x +5 ) \: . \: (2x - 5)$

$= (2x) {}^{2} - 5 {}^{2}$

$= 4x {}^{2} - 25$

t)

$= (3x - 2) \: . \: (3x + 2)$

$= (3x) {}^{2} - 2 {}^{2}$

$= 9x {}^{2} - 4$

Att. Makaveli1996