Question

Calcule os produtos abaixo:

a (2×+3)²

b ( 4y+5)²

c (3a+6)²

d (5a+5b)²

e (6a-4)²

f (5x-3)²

g (4y-5x)²

h (4y+5) (4y-5)

i ( 5a+5b) (5a-5b)

j ( 6a+4) (6a-4)

K (5×+3) (5×-3)

PRECISO URGENTE DISSO !!!

Answer 1

Resposta:

Explicação passo a passo:

a.

(2x+3)(2x+3)=

4x²+6x+6x+9=

4x²+12x+9

b.

(4y+5)(4y+5)=

16y²+20y+20y+25=

16y²+40y+25

c.

(3a+6)(3a+6)=

9a²+18a+18a+36=

9a²+36a+36

d.

(5a+5b)(5a+5b)=

25a²+25ab+25ab+25b²=

25a²+50ab+25b²

e.

(6a-4)(6a-4)=

36a²-24a-24a+16=

36a²-48a+16

f.

(5x-3)(5x-3)=

25x²-15x-15x+9=

25x²-30x+9

g.

(4y-5x)(4y-5x)=

16y²-20xy-20xy+25x²=

16y²-40xy+25x²

h.

(4y+5)(4y-5)=

16y²+20y-20y-25=

16y²-25

i.

(5a+5b)(5a-5b)=

25a²-25ab+25ab-25b²=

25a²-25b²

j.

(6a+4)(6a-4)=

36a²-24a+24a-16=

36a²-16

k.

(5x+3)(5x-3)=

25x²+15x-15x-9=

25x²-9