Question

Calcule os possíveis valores de X na equação​

Answer 1

$A = \frac{1}{2} + \frac{1}{3} = \frac{5}{6}\\\\B = \frac{x}{4} + \frac{1}{x} = \frac{x^{2} + 4}{4x}\\\\\frac{A}{B} = \frac{20x}{6x^{2} + 24} = \frac{1}{2} \\\\6x^{2} + 24 = 40x\\6x^{2} + 24 - 40x = 0$

Resolve a eq do 2 grau:

$x_{1} = 2/3\\x_{2} = 6$