Question

calcule os números irracionais.
$3\sqrt{100} + 5 \sqrt{3 } - 3 \sqrt{81} + 2 \sqrt{243}$

$9 \sqrt{2} + 8 + 4 \sqrt{3} - 3 \sqrt{4} - 3 \sqrt{4} + 6 \sqrt{2} - 2 \sqrt{3}$

Answer 1

$\boxed{\boxed{Ola\´ \: \: Ingridcoutinho} }$

$3\sqrt{100} + 5 \sqrt{3 } - 3 \sqrt{81} + 2 \sqrt{243}$
$= 3 \cdot 10 + 5 \sqrt{3} - 3 \cdot 9 + 2 \sqrt{3^2 \cdot 3^2 \cdot 3} \\ = 30 -27 + 5 \sqrt{3} + 2 \cdot 9 \sqrt{3} \\ = 3 + (5 + 18) \sqrt{3}$

$= \boxed{\boxed{3 + 23 \sqrt{3}} }} \end{array}\qquad\checkmark$


$9 \sqrt{2} + 8 + 4 \sqrt{3} - 3 \sqrt{4} - 3 \sqrt{4} + 6 \sqrt{2} - 2 \sqrt{3}$
$9\sqrt{2} + 8 + 4 \sqrt{3} - 3 \sqrt{4} - 3 \sqrt{4} + 6 \sqrt{2} - 2 \sqrt{3} \\ = 9 \sqrt{2} + 6 \sqrt{2} + 4 \sqrt{3} - 2 \sqrt{3} - 3 \sqrt{4} - 3 \sqrt{4} + 8 \\ = 15 \sqrt{2} + 2 \sqrt{3} - 6 \sqrt{4} + 8 \\ = 15 \sqrt{2} + 2 \sqrt{3} - 6.2 + 8 \\ = 15 \sqrt{2} + 2 \sqrt{3} - 12 + 8$
$= \boxed{\boxed{15 \sqrt{2} + 2 \sqrt{3} - 4} }} \end{array}\qquad\checkmark$



$\textbf{Bons estudos}$ !