Question

Calcule os logaritmo
Log5 1/25
Log4 8
Log1/2 16
Log7 1

Answer 1

$log_{5}( \frac{1}{25} ) \\ {5}^{x} = \frac{1}{25} \\ {5}^{x} = {25}^{ - 1} \\ {5}^{x} = {5}^{ 2 - 1} \\ x = 2 - 1 \\ x = 1$

$log_{4}(8) \\ {4}^{x} = 8 \\ {4}^{x} = {4}^{2} \\ x = 2$

$log_{ \frac{1}{2} }(16) \\ { \frac{1}{2} }^{x} = 16 \\ {2}^{x} = {2}^{8} \\ x = 8$

$log_{7}(1) \\ {7}^{x} = 1 \\ {7}^{x} = {7}^{0} \\ x = 0$