Question

Calcule os determinantes:$\left[\begin{array}{ccc}6+ \sqrt{2} & \sqrt{15} + \sqrt{3} &\\- \sqrt{15} - \sqrt{3} &6- \sqrt{2} &\\\end{array}\right]$

Answer 1

  6 + √2      √15 + √3
-√15 - √3     6 - √2  

= 

(6² - (√2)²) + ((√15)² - (√3)²)= 

(36 - 2) + (15 - 3) = 

34 + 12 = 

46