Question

calcule os determinantes :
a) 6 2
4 3

b)-3 -8
1 2

c) 6 10

3 5

d) a b
a+b a+b

e) [sen X (cos X)-1]
[-sen X (cos X) -1]

f) [cos A sen B
sen B cos A]​

Answer 1

A) (6x3)-(2x4)= 10
B) (-3x2)-(-8x1)= 2
C) (6x5)-(10x3)= 0
D) (ax(a+b))-(bx(a+b))= a^2+ab-ba-b^2= a^2-b^2
E) (senx x cosx-1)- (cosx-1 x -senx)
F) (CosA)^2- (senB)^2