Calcule os determinantes:
-3 2
3 -4
8 3
5 4
0 ¼
4 1
¾ -5
1/5 8
Soluções para a tarefa
Respondido por
2
Olá
![\left[\begin{array}{ccc}-3&2\\3&-4\\\end{array}\right] =((-3)\cdot(-4))-(3\cdot2)=12-6=\boxed{6}](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%26amp%3B2%5C%5C3%26amp%3B-4%5C%5C%5Cend%7Barray%7D%5Cright%5D+%3D%28%28-3%29%5Ccdot%28-4%29%29-%283%5Ccdot2%29%3D12-6%3D%5Cboxed%7B6%7D "\left[\begin{array}{ccc}-3&2\\3&-4\\\end{array}\right] =((-3)\cdot(-4))-(3\cdot2)=12-6=\boxed{6}")
![\left[\begin{array}{ccc}8&3\\5&4\\\end{array}\right]=(8\cdot 3)-(5\cdot3)=24-15=\boxed{9}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%26amp%3B3%5C%5C5%26amp%3B4%5C%5C%5Cend%7Barray%7D%5Cright%5D%3D%288%5Ccdot+3%29-%285%5Ccdot3%29%3D24-15%3D%5Cboxed%7B9%7D "\left[\begin{array}{ccc}8&3\\5&4\\\end{array}\right]=(8\cdot 3)-(5\cdot3)=24-15=\boxed{9}")
![\left[\begin{array}{ccc}0& \frac{1}{4} \\4&1\\\end{array}\right]=(0\cdot1)-(\mathtt{\diagup\!\!\!\!4\cdot \frac{1}{\diagup\!\!\!\!\!4} )}=0-1=\boxed{-1}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26amp%3B+%5Cfrac%7B1%7D%7B4%7D+%5C%5C4%26amp%3B1%5C%5C%5Cend%7Barray%7D%5Cright%5D%3D%280%5Ccdot1%29-%28%5Cmathtt%7B%5Cdiagup%5C%21%5C%21%5C%21%5C%214%5Ccdot+%5Cfrac%7B1%7D%7B%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%214%7D+%29%7D%3D0-1%3D%5Cboxed%7B-1%7D "\left[\begin{array}{ccc}0& \frac{1}{4} \\4&1\\\end{array}\right]=(0\cdot1)-(\mathtt{\diagup\!\!\!\!4\cdot \frac{1}{\diagup\!\!\!\!\!4} )}=0-1=\boxed{-1}")
![\left[\begin{array}{ccc} \frac{3}{4} &-5\\ \\ \frac{1}{5} &8\\\end{array}\right]=\mathtt{ (\frac{3}{\diagup\!\!\!\!4}\cdot\diagup\!\!\!\!8)-( \frac{1}{\diagup\!\!\!\!5}\cdot-\diagup\!\!\!\!5 ) } \\ ~~~~~~~~~~ ~~~~~~~=(3\cdot2)-(-1)=6+1=\boxed{7}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D+%5Cfrac%7B3%7D%7B4%7D+%26amp%3B-5%5C%5C++%5C%5C+%5Cfrac%7B1%7D%7B5%7D+%26amp%3B8%5C%5C%5Cend%7Barray%7D%5Cright%5D%3D%5Cmathtt%7B+%28%5Cfrac%7B3%7D%7B%5Cdiagup%5C%21%5C%21%5C%21%5C%214%7D%5Ccdot%5Cdiagup%5C%21%5C%21%5C%21%5C%218%29-%28+%5Cfrac%7B1%7D%7B%5Cdiagup%5C%21%5C%21%5C%21%5C%215%7D%5Ccdot-%5Cdiagup%5C%21%5C%21%5C%21%5C%215+%29+%7D+%5C%5C+%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E+%7E%7E%7E%7E%7E%7E%7E%3D%283%5Ccdot2%29-%28-1%29%3D6%2B1%3D%5Cboxed%7B7%7D "\left[\begin{array}{ccc} \frac{3}{4} &-5\\ \\ \frac{1}{5} &8\\\end{array}\right]=\mathtt{ (\frac{3}{\diagup\!\!\!\!4}\cdot\diagup\!\!\!\!8)-( \frac{1}{\diagup\!\!\!\!5}\cdot-\diagup\!\!\!\!5 ) } \\ ~~~~~~~~~~ ~~~~~~~=(3\cdot2)-(-1)=6+1=\boxed{7}")
Terezinhasouza:
Muito obrigada!!!!1 Valeu!!!Abraço.
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