Question

calcule o x nos triângulos abaixo
ME AJUDEM PFVR, É PRA AGORAAA (PS: PRECISO DOS CÁLCULOS)​

Answer 1

$\textsf{Leia abaixo}$

Explicação passo-a-passo:

a)

$\large\boxed{\begin{array}{l}\rm \: x + 80\textdegree + 30\textdegree = 180\textdegree \\ \\ \rm \: x + 110\textdegree = 180\textdegree \\ \\ \rm \: x = 180\textdegree - 110\textdegree \\ \\ \boxed{ \boxed{ \rm{x = 70\textdegree}}} \checkmark\end{array}}$

b)

$\large\boxed{\begin{array}{l}\rm \: 5x + 4x + 45\textdegree = 180\textdegree \\ \\ \rm \: 9x = 180\textdegree - 45\textdegree \\ \\ \rm \: 9x = 135\textdegree \\ \\ \rm \: x = \dfrac{135\textdegree}{9} \\ \\ \boxed{ \boxed{\rm{x = 15\textdegree}}} \checkmark\end{array}}$

c)

$\large\boxed{\begin{array}{l} \rm \: x + x + 10\textdegree + 3x - 50\textdegree = 180\textdegree \\ \\ \rm \: 5x - 40\textdegree = 18 0\textdegree \\ \\ \rm \: 5x = 180\textdegree + 40\textdegree \\ \\ \rm \: 5x = 220\textdegree \\ \\ \rm \: x = \dfrac{220\textdegree}{5} \\ \\ \boxed{ \boxed{ \rm{x = 44\textdegree}}}\checkmark\end{array}}$

d)

$\large\boxed{\begin{array}{l} \rm \: x + 60\textdegree + 75\textdegree = 180\textdegree \\ \\ \rm \: x + 135\textdegree = 180\textdegree \\ \\ \rm \: x = 180\textdegree - 135\textdegree \\ \\ \boxed{ \boxed{\rm{x = 45\textdegree}}} \checkmark\end{array}}$