Matemática, perguntado por fuckyisnel, 5 meses atrás

calcule o x nos triângulos abaixo
ME AJUDEM PFVR, É PRA AGORAAA (PS: PRECISO DOS CÁLCULOS)​

Anexos:

Soluções para a tarefa

Respondido por Usuário anônimo
3

\textsf{Leia abaixo}

Explicação passo-a-passo:

a)

\large\boxed{\begin{array}{l}\rm \: x + 80\textdegree + 30\textdegree = 180\textdegree \\ \\  \rm \:  x + 110\textdegree = 180\textdegree \\  \\  \rm \: x = 180\textdegree - 110\textdegree \\  \\  \boxed{ \boxed{ \rm{x = 70\textdegree}}} \checkmark\end{array}}

b)

\large\boxed{\begin{array}{l}\rm \: 5x + 4x + 45\textdegree = 180\textdegree \\  \\  \rm \: 9x = 180\textdegree - 45\textdegree \\  \\  \rm \: 9x = 135\textdegree \\  \\  \rm \: x =  \dfrac{135\textdegree}{9}  \\  \\   \boxed{ \boxed{\rm{x = 15\textdegree}}} \checkmark\end{array}}

c)

\large\boxed{\begin{array}{l}  \rm \: x + x + 10\textdegree + 3x - 50\textdegree = 180\textdegree \\  \\  \rm \: 5x - 40\textdegree = 18 0\textdegree \\  \\  \rm \: 5x = 180\textdegree + 40\textdegree \\  \\  \rm \: 5x = 220\textdegree \\  \\  \rm \: x =  \dfrac{220\textdegree}{5}  \\  \\  \boxed{ \boxed{ \rm{x = 44\textdegree}}}\checkmark\end{array}}

d)

\large\boxed{\begin{array}{l} \rm \: x + 60\textdegree + 75\textdegree = 180\textdegree \\  \\  \rm \: x + 135\textdegree = 180\textdegree \\  \\  \rm \: x = 180\textdegree - 135\textdegree \\  \\   \boxed{ \boxed{\rm{x = 45\textdegree}}} \checkmark\end{array}}

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