Question

calcule o vertice das parábolas.
A- f(x)=2x²-4x
B- f(x)=2x²
C- f(x)=4x²-8x+4
D- f(x)=1+x+x²
E- f(x)=3x²+2x+1

Answer 1

Boa noite

a)

f(x) = 2x² - 4x

vértice
Vx = -b/2a = 4/4 = 1
Vy = f(1) = 2 - 4 = -2

b)

f(x) = 2x²

vértices
Vx = -b/2a = 0
Vy = f(0) = 0

c)

f(x) = 4x² - 8x + 4

vértice

Vx = -b/2a = 8/8 = 1
Vy = f(1) = 4 - 8 + 4 = 0 

d)

f(x) = x² + x + 1

vértice

Vx = -b/2a = -1/2
Vy = f(-1/2) = 1/4 - 1/2 + 1 = 1/4 - 2/4 + 4/4 = 3/4 

e)

f(x) = 3x² + 2x + 1

vértice

Vx = -b/2a = -2/6 = -1/3
Vy = f(-1/3) = 3/9 - 2/3 + 1 = 3/9 - 6/9 + 9/9 = 6/9 = 2/3