Question

Calcule o valordas medidas indicadas nos triângulos Retângulos.
obs: desculpem o Paint rsrsrsrs

Answer 1

Bora lá .. 

letra a : 

$Sen60 = \frac{12 \sqrt{3} }{a} \\ \\ a = \frac{12 \sqrt{3} }{ \sqrt{ \frac{3}{2} } } \\ \\ a = 24 \\ \\ \\ cos60 = \frac{b}{24} \\ \\ b = 24. \frac{1}{2} = \frac{24}{2} = 12 \\ \\ \frac{b}{a} = \frac{12}{24} = \frac{1}{2}$

Letra b :
$Sen45 = \frac{20 \sqrt{2} }{x} \\ \\ x = \frac{20 \sqrt{2} }{2 \sqrt{2} } \\ \\ x = 20 \\ \\ \\ cos 45 = \frac{y}{20} \\ \\ y = 20. \frac{1}{2} = \frac{20}{2} = 10 \\ \\ \\ \frac{x}{y} = \frac{20}{10} = 2$

Answer 2

a)

Valor de a = 

Seno de 60 = 12√3 / a
√3 / 2 = 12√3 / a
√3a=24√3
a=24√3/√3
a=24


Valor de b :

Cosseno de 60 = 12√3 / b
1/2 = 12√3 / b
b=24√3

b)
Valor de y:

Seno de 45 = y / 20√2
√2 / 2 = y / 20√2
2y=20√4
2y=20.2
2y=40
y=40/2
y=20

Valor de x:

Cosseno de 45 = x / 20√2

√2 / 2  = x / 20√2

2x=20√4
2x=20.2
2x=40
x=40/2
x=20