Question

Calcule o valor x e y.

Answer 1

Explicação passo-a-passo:

• $\sf cos~45^{\circ}=\dfrac{cateto~adjacente}{hipotenusa}$

$\sf \dfrac{\sqrt{2}}{2}=\dfrac{x}{20\sqrt{2}}$

$\sf 2x=20\sqrt{2}\cdot\sqrt{2}$

$\sf 2x=20\cdot2$

$\sf 2x=40$

$\sf x=\dfrac{40}{2}$

$\sf x=20$

• $\sf sen~45^{\circ}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \dfrac{\sqrt{2}}{2}=\dfrac{y}{20\sqrt{2}}$

$\sf 2y=20\sqrt{2}\cdot\sqrt{2}$

$\sf 2y=20\cdot2$

$\sf 2y=40$

$\sf y=\dfrac{40}{2}$

$\sf y=20$

Answer 2

Resposta:

Explicação passo-a-passo:

Hipotenusa = $20\sqrt{x2}$

Sen 45º = Cos 45º = $\frac{\sqrt{2} }{2}$

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sen a = cateto oposto/hipotenusa

$\frac{\sqrt{2} }{2} = \frac{Y}{20\sqrt{2} }$          

$Y = \frac{\sqrt{2} }{2} * 20\sqrt{2} = 20$

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cos a = cateto adjacente/hipotenusa

$\frac{\sqrt{2} }{2} = \frac{X}{20\sqrt{2} }$

$X = \frac{\sqrt{2} }{2} * 20\sqrt{2} = 20$

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$X = Y = 20$