calcule o valor real da expressão E=[(x²+y)ⁿ⁺⁴ + (x+y²)ⁿ⁺³ + (x²+y²)ⁿ⁺²] quando x = 2, y= -1 2 n= -2 buguei... quem puder ajudar, agradeço!
medicisolucoes:
Y igual a quanto? -12 ou -1/2?
12
-12
Soluções para a tarefa
Respondido por
1
E=[(x²+y)ⁿ⁺⁴ + (x+y²)ⁿ⁺³ + (x²+y²)ⁿ⁺²] ![E=[(x^2+y)^n^+^4+(x+y^2)^n^+^3 + (x^2+y^2)^n^+^2]\\\\
E=[(2^2+(-12))^(^-^2^)^+^4+(2+(-12)^2)^(^-^2^)^+^3 + (2^2+(-12)^2)^(^-^2^)^+^2]\\
Agora fica mais facil
E=[(4-12)^2+(2+144)^1 + (5+144)^0]\\\\
E=[(-8)^2+(146)^1 + (149)^0]\\\\
E=[64+146+1]\\\\
E=[211]\\\\](https://tex.z-dn.net/?f=E%3D%5B%28x%5E2%2By%29%5En%5E%2B%5E4%2B%28x%2By%5E2%29%5En%5E%2B%5E3+%2B+%28x%5E2%2By%5E2%29%5En%5E%2B%5E2%5D%5C%5C%5C%5C%0AE%3D%5B%282%5E2%2B%28-12%29%29%5E%28%5E-%5E2%5E%29%5E%2B%5E4%2B%282%2B%28-12%29%5E2%29%5E%28%5E-%5E2%5E%29%5E%2B%5E3+%2B+%282%5E2%2B%28-12%29%5E2%29%5E%28%5E-%5E2%5E%29%5E%2B%5E2%5D%5C%5C%0A%0AAgora+fica+mais+facil%0A%0AE%3D%5B%284-12%29%5E2%2B%282%2B144%29%5E1+%2B+%285%2B144%29%5E0%5D%5C%5C%5C%5C%0AE%3D%5B%28-8%29%5E2%2B%28146%29%5E1+%2B+%28149%29%5E0%5D%5C%5C%5C%5C%0AE%3D%5B64%2B146%2B1%5D%5C%5C%5C%5C%0AE%3D%5B211%5D%5C%5C%5C%5C "E=[(x^2+y)^n^+^4+(x+y^2)^n^+^3 + (x^2+y^2)^n^+^2]\\\\
E=[(2^2+(-12))^(^-^2^)^+^4+(2+(-12)^2)^(^-^2^)^+^3 + (2^2+(-12)^2)^(^-^2^)^+^2]\\
Agora fica mais facil
E=[(4-12)^2+(2+144)^1 + (5+144)^0]\\\\
E=[(-8)^2+(146)^1 + (149)^0]\\\\
E=[64+146+1]\\\\
E=[211]\\\\")
veja se é isso
![E=3\times[(x^2+y)^n^+^4+(x+y^2)^n^+^3 + (x^2+y^2)^n^+^2]\\\\
E=3\times[(2^2+(-1))^(^-^2^)^+^4+(2+(-1)^2)^(^-^2^)^+^3 + (2^2+(-1)^2)^(^-^2^)^+^2]\\\\
E=3\times[(4-1)^2+(2+1)^1 + (4+1)^0]\\\\
E=3\times[(3)^2+(3)^1 + (5)^0]\\\\
E=3\times[9+3 +1]\\\\
E=3\times[13]\\\\
E=39\\\\](https://tex.z-dn.net/?f=E%3D3%5Ctimes%5B%28x%5E2%2By%29%5En%5E%2B%5E4%2B%28x%2By%5E2%29%5En%5E%2B%5E3+%2B+%28x%5E2%2By%5E2%29%5En%5E%2B%5E2%5D%5C%5C%5C%5C%0AE%3D3%5Ctimes%5B%282%5E2%2B%28-1%29%29%5E%28%5E-%5E2%5E%29%5E%2B%5E4%2B%282%2B%28-1%29%5E2%29%5E%28%5E-%5E2%5E%29%5E%2B%5E3+%2B+%282%5E2%2B%28-1%29%5E2%29%5E%28%5E-%5E2%5E%29%5E%2B%5E2%5D%5C%5C%5C%5C%0AE%3D3%5Ctimes%5B%284-1%29%5E2%2B%282%2B1%29%5E1+%2B+%284%2B1%29%5E0%5D%5C%5C%5C%5C%0AE%3D3%5Ctimes%5B%283%29%5E2%2B%283%29%5E1+%2B+%285%29%5E0%5D%5C%5C%5C%5C%0AE%3D3%5Ctimes%5B9%2B3+%2B1%5D%5C%5C%5C%5C%0AE%3D3%5Ctimes%5B13%5D%5C%5C%5C%5C%0AE%3D39%5C%5C%5C%5C%0A "E=3\times[(x^2+y)^n^+^4+(x+y^2)^n^+^3 + (x^2+y^2)^n^+^2]\\\\
E=3\times[(2^2+(-1))^(^-^2^)^+^4+(2+(-1)^2)^(^-^2^)^+^3 + (2^2+(-1)^2)^(^-^2^)^+^2]\\\\
E=3\times[(4-1)^2+(2+1)^1 + (4+1)^0]\\\\
E=3\times[(3)^2+(3)^1 + (5)^0]\\\\
E=3\times[9+3 +1]\\\\
E=3\times[13]\\\\
E=39\\\\")
veja se é isso
Até eu buguei kkk
hahaha tava difícil... obrigado. estou desde ontem tenatando fazer, o professor não explica
bro, esqueci de acrescentar o 3 antes do colchete... basta multiplicar o resultado final por três?
e o y é igual a -1 T.T T.T T.T
vou colocar abaixo
agradeço!!!!!
Prontinho e confirmado. 39
isso!! salvou minha vida! muitp obrigado!
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