Question

calcule o valor numerico de (x+y)2 e do x2 em cada caso
a)x=3 e y =4
b)x=-7 e y=7
c)x=6 e y=-5
d)x=0 e y=9
e)x=y=1
f)x= 1, 1 e y=0,4

Answer 1

Resposta:

Explicação passo-a-passo:

a) $(3+4)^2=7^2=49\ e\ 3^2=9$

b) $(-7+7)^2=0^2=0\ e\ (-7)^2=49$

c) $(6-5)^2=1^2=1\ e\ 6^2=36$

d) $(0+9)^2=9^2=81\ e\ 0^2=0$

e) $(1+1)^2=2^2=4\ e\ 1^2=1$

f)

$(1,1+0,4)^2=(1,5)^2=(\frac{15}{10})^2=\frac{225}{100}=\frac{45}{20}=\frac{9}{4}\ e\ \\(1,1)^2=(\frac{11}{10})^2=\frac{121}{100}$