Question

Calcule o valor numérico de x= -b+ (raiz quadrada de:) b2-4ac/2a
Para a=2,b=10 e c=12

Answer 1

=> Calcular o valor numérico de "X" em:

(- b +/- √(b² - 4ac))/2a   ...para a = 2, b = 10 ..e c = 12

(-(10) +/- √((10)² - 4.2.12))/2.(2)

(-(10) +/- √((100 - 96))/2.(2)

(-(10) +/- √4)/4

(-10 +/- 2)/4

X´= (-10 + 2)/4 = -8/4 = -2

X´´ = (-10 - 2)/4 = -12/4 = -3

o valor de X = -2 ..ou -3
 

Espero ter ajudado

Answer 2

$x=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-10+\sqrt{10^2-4.2.12}}{2.2}=\frac{-10+\sqrt{100-96}}{4}=\frac{-10+\sqrt4}{4}=\\ \\ \frac{-10+2}{4}=\frac{-8}{4}=-2$