Question

calcule o valor numerico das expressoes c) 2x³-x²+x sobre 2-1,para x+raiz de tres

Answer 1

c) 
(2x³ - x² + x)/2 - 1/1 --> x = √3
[2.(√3)³-(√3)²+√3]/2 - 1/1 = 
[2.(√3)².√3 - 3 + √3]/2 - 1/1 = 
[2.3.√3-3+√3]/2 - 1/1 = 
[6√3 - 3 + √3]/2 - 1/1 = 
[6√3+√3-3]/2 - 1/1 = 
[7√3-3]/2 - 1/1 = 
[7√3-3]/2 - 2/2 = 
(7√3-3-2)/2 = 
(7√3-5)/2

Answer 2

$\frac{2x^3-x^2+x}{2-1} =$ ---------> x = √3

$\frac{2 (\sqrt{3})^3 - ( \sqrt{3} )^2+( \sqrt{3)} }{1} =$

$2( \sqrt{3^2.3}) - 3 + \sqrt{3} =$

2.3√3 - 3 + √3 = 6√3 - 3 + √3 = 7√3 - 3