Question

Calcule o valor numérico da função f (x) =x ao quadrado - 4x + 3 para x = 1/2

Answer 1

$f(x) = x^2 - 4x + 3 \\ \\ f(\frac{1}{2}) = (\frac{1}{2})^2 - 4 * \frac{1}{2} + 3 \\ \\ f(\frac{1}{2}) = \frac{1}{4} - \frac{4}{2} + 3 \\ \\ f(\frac{1}{2}) = \frac{1}{4} - 2 + 3 \\ \\ f(\frac{1}{2}) = \frac{1}{4} +1 \\ \\ f(\frac{1}{2}) = \frac{1 + 4}{4} \\ \\ =\ \textgreater \ f(\frac{1}{2}) = \frac{5}{4}$

Answer 2

✅ Depois de resolver os cálculos, concluímos que o valor numérico da referida função quadrática é:

      $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf f\Bigg(\frac{1}{2} \Bigg) = \frac{5}{4} \:\:\:}}\end{gathered} }$

Seja a função quadrática:

     $\Large\displaystyle\begin{gathered} f(x) = x^{2} - 4x + 3\end{gathered}$

Se:

                $\Large\displaystyle\begin{gathered} x = \frac{1}{2} \end{gathered}$

Para calcular o valor numérico da função devemos substituir a incógnita pelo respectivo valor, ou seja:

   $\Large\displaystyle\begin{gathered} f\Bigg(\frac{1}{2} \Bigg) = \Bigg(\frac{1}{2} \Bigg)^{2} - 4\Bigg(\frac{1}{2} \Bigg) + 3 \end{gathered}$

                $\Large\displaystyle\begin{gathered} = \frac{1}{4} - \frac{4}{2} + 3 \end{gathered}$

                $\Large\displaystyle\begin{gathered} = \frac{1 - 8 + 12}{4} \end{gathered}$

                $\Large\displaystyle\begin{gathered} = \frac{5}{4} \end{gathered}$

Portanto, o valor numérico da função é:

      $\Large\displaystyle\begin{gathered} f\Bigg(\frac{1}{2} \Bigg) = \frac{5}{4} \end{gathered}$

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