Question

Calcule o valor numérico da equação (em anexo)

Answer 1

$\dfrac{x^2+3x+6}{\frac{x}{2}+3}=4\\ \\ \\ x^2+3x+6=4.\left(\dfrac{x}{2}+3\right)\\ \\ \\ x^2+3x+6=\dfrac{4.x}{2}+4.3\\ \\ \\ x^2 +3x+6=2x+12\\ \\ \\ x^2+3x-2x+6-12=0\\ \\ \\ x^2+x-6=0\\ \\ \\ \Delta=b^2-4.a.c\\ \\ \Delta=1-4.1.(-6)\\ \\ \Delta=1+24 \to \Delta=25\to\sqrt{\Delta}=5\\ \\ \\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\ \\ \\ x=\dfrac{-1\pm5}{2}\\ \\ \\ x'=-6/2\\ \boxed{x'=-3}\\ \\ x''=4/2\\ \boxed{x''=2}$

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