Question

calcule o valor dos seguintes arranjos
a- A9,2
b- A10,6

Answer 1

Resposta:

Olá boa tarde!

A expressão para o cálculo do arranjo simples é:

$A_{n,p} = \frac{n!}{(n-p)!}$

a)

n = 9

p = 2

$A_{9,2} = \frac{9!}{(9-2)!} \\\\A_{9,2} = \frac{9!}{7!} \\\\A_{9,2} = \frac{9*8*7!}{7!} \\\\A_{9,2} = 9*8 \\\\A_{9,2} = 72}$

b)

n = 10

p = 6

$A_{10,6} = \frac{10!}{(10-6)!} \\\\A_{10,6} = \frac{10!}{4!} \\\\A_{10,6} = \frac{10*9*8*7*6*5*4!}{4!} \\\\A_{10,6} = 10*9*8*7*6*5 \\\\A_{10,6} = 151.200}$