Question

calcule o valor dos logaritmos:

a) log6 36
b) log1/4 2√2

Answer 1

a) log6 36 ==> log 6^2 ==> 2log 6 ==> 2.1 ==> 2
                             6                   6

b) log 2√2 = y ==> 1/4^y = (2.2^1/2) ==> (2^-2)y = 2^3/2
        1/4

- 2y = 3 ==> - 4y = 3(-1) ==> 4y = - 3 ==> y = - 3/4
          2