Question

calcule o valor dos angulos complementares A e B, sendo que, A=3x+40 e B=2 X+40

Answer 1

A + B = 90° (complementares)
3x+40 + 2x+40 = 90
5x +80 = 90
5x = 90 -80
5x = 10
x = 10/5
x = 2

A = 3x + 40 = 3.2 + 40 = 6+40 = 46
B = 2x + 40 = 2. 2 + 40 = 4 + 40 = 44

Answer 2

Olá, bom dia! ☺

Bem, vamos lá ...

Prezado amigo (a), com base no enunciado acima, podemos compreender que:

$\displaystyle \mathsf {A + B = 90^o}$

$\displaystyle \mathsf {3x+40 + 2x+40 = 90}$

$\displaystyle \mathsf {5x +80 = 90}$

$\displaystyle \mathsf {5x = 90 -80}$

$\displaystyle \mathsf {5x = 10}$

$\displaystyle \mathsf {x =\dfrac {10}{5}}$

$\displaystyle \mathbf {x = 2}$

Valor do ângulo "A":

$\displaystyle \mathsf {A = 3x + 40}$

$\displaystyle \mathsf {A=3\cdot 2 + 40}$

$\displaystyle \mathsf {A=6+40}$

$\displaystyle \mathbf {A=46}$

Valor do ângulo "B":

$\displaystyle \mathsf {B = 2x + 40}$

$\displaystyle \mathsf {B=2\cdot 2 + 40}$

$\displaystyle \mathsf {B=4 + 40}$

$\displaystyle \mathbf {B=44}$