Question

Calcule o valor do discriminante (delta)
.
.t (x) -x^2-9
.
.v (x)= x^2/4+2x

Answer 1

.t (x) -x^2 -9 => a=-1 , b=0 , c=-9
∆= b² -4 a.c
∆= 0² -4.(-1).(-9)
∆= 0 - 36
∆= -36 ✓
.
.v (x)= x^2/4 +2x => a=1/4 , b=2 , c= 0
∆= b² -4 a.c
∆= 2² -4.(1/4).0
∆= 4 - 0
∆= 4 ✓