Question

calcule o valor de X,Y, Z dos sistema
X-3y+ 5z =1
x+2y +z = 12
2x- y = 10
resposta

5cf22aaea0a37d90bc003fd67e37e1c9.docx

Answer 1

$S = \left( x = \frac{63}{10} ,y = \frac{13}{5} ,z = \frac{1}{2} \right)$

$\begin{gathered}\begin{cases} { x - 3y + 5z = 1 }\\ {x + 2y + z = 12 } \\ 2x - y = 10 \end{cases}\end{gathered}$

$\underbrace{{ \begin{gathered}\begin{cases} { x - 3y + 5z = 1 }\\ { x + 2y + z = 12 \: \begin{gathered}\begin{cases} { - x - 2y - z = - 12 } \end{cases}\end{gathered} } \end{cases}\end{gathered} } {  }}_{  - 5y + 4z = - 11 }\\ \\ \underbrace{{ \begin{gathered}\begin{cases} { x - 3y + 5z = 1\begin{gathered}\begin{cases} { - 2x + 6y - 10z = - 2 } \end{cases}\end{gathered} }\\ { 2x - y = 10 } \end{cases}\end{gathered} } {  }}_{ 5y - 10z = 8 }$

Organizei as equações

$- 5y + 4z = - 11 \\ 5y - 10z = 8 \: \: \: \: \\ \begin{gathered}\begin{cases} { - 5y + 4z = - 11 }\\ { 5y - 10z = 8 } \end{cases}\end{gathered} \\ - 6z = - 3 \\ z = \frac{1}{2} \\ - 5y + 4 \times \frac{1}{2} = - 11 \\ y = \frac{13}{5}$

Agora encontre o x

$2x - \frac{13}{5} = 10 \\ 2x = 10 + \frac{13}{5} \\ 2x = \frac{63}{5} \\ x = \frac{63}{10}$

$Bom \: Estudos \\ \displaystyle\int_ \empty ^ \mathbb{C}     \frac{ - b \: ± \:  \sqrt{ {b}^{2} - 4 \times a \times c } }{2 \times a} d{ t } \boxed{ \boxed{ \mathbb{\displaystyle\Re}\sf{ \gamma  \alpha }\tt{ \pi}\bf{ \nabla}}}$