Question

Calcule o valor de x',x": A) 2x elevado a 2 - 8x + 8 = 0

Answer 1

2x^{2}-8x+8=o

delta=-8^{2}-4.8.2
delta=64-4.16
delta=64-64
delta=0

x=-b+e-delta/a.2
x=8+-0/4
x`=2
x``=2

Answer 2

2x² - 8x + 8 = 0 (:2)
x² - 4x + 4 = 0
a = 1; b = - 4; c = 4
Δ = b² - 4ac
Δ = (-4)² - 4.1.4
Δ = 16 - 16
Δ = 0

x = - b +/- √Δ    = - (-4) +/- √0
      ---------------    ------------------
            2a                 2.1

x' = x = 4/2 = 2

R.: x = 2