Question

calcule o valor de X, utilizando o Teorema de Pitágoras ​

Answer 1

Resposta:

X=2√3

Explicação passo-a-passo:

$\boxed{ \boxed{ \underbrace{{a}^{2} = {b}^{2} + {c}^{2}} }}$

${4}^{2} = {2}^{2} + {x}^{2} \\ \\ 16 - 4 = {x}^{2} \\ \\ 12 = {x}^{2} \\ \\ x = \sqrt{12} \\ \\ x = \sqrt{ {2}^{2} \times 3} \\ \\ \boxed{\boxed{ \checkmark \boxed{x = 2 \sqrt{3} }}}$

Answer 2

$\large \boxed{ \begin{array}{l} a {}^{2} = b {}^{2} + c {}^{2} \\ 4 {}^{2} = 2 {}^{2} + x {}^{2} \\ 16 = 4 + x {}^{2} \\ 16 - 4 = x {}^{2} \\ x {}^{2} \: = \: 12 \\ x = \sqrt{12} \\ \boxed{ \boxed{x = 2 \sqrt{3} }}\end{array}}$