Question

Calcule o valor de x usando o teorema de Pitágoras

Answer 1

14² = (5√3)² + x²

196 = 25 .3 + x²

196 = 75 + x²

x² = 196 - 75

x² = 121

x = √121
 
x = 11           ok

Answer 2

$h^{2} = a^{2} + b^{2} -\ \textgreater \ 14 ^{2} = (5 \sqrt{3}) ^{2} + x^{2} -\ \textgreater \ 196= 75+ x^{2} -\ \textgreater \ x= \sqrt{121} \\ x= 11$