Question

calcule o valor de x nos triângulos retângulos​

Answer 1

Explicação passo-a-passo:

$a){a}^{2} = {b}^{2} + {c}^{2} \\ {x}^{2} = {20}^{2} + {15}^{2} \\ {x}^{2} = 400 + 225 \\ {x}^{2} = 625 \\ x = \sqrt{625} \\ x = 25 \\ \\ \\ \\ b) {a}^{2} = {b}^{2} + {c}^{2} \\ {x}^{2} = {6}^{2} + {8}^{2} \\ {x}^{2} = 36 + 64 \\ {x}^{2} = 100 \\ x = \sqrt{100} \\ x = 10 \\ \\ \\ c) {a}^{2} = {b}^{2} + {c}^{2} \\ {10}^{2} = {6}^{2} + {x}^{2} \\ 100 = 36 + {x}^{2} \\ { - x}^{2} = 36 - 100 \\ - {x}^{2} = - 64 \: ( - 1) \\ {x}^{2} = 64$