Question

calcule o valor de x nos triângulos retângulos

Answer 1

a) a²=b²+c²

x²= 6²+8²

x²= 36+64

x²=100

x= √100

x=10

b)a²=b²+c²

x²=4²+5²

x²=16+25

x²=41

x=√41

x= 6,40

c) 3√11, x , 3√2

(3√11)² = x² + (3√2)²

9.11 = x² + 9.2

99 = x² + 18

x² = 99 - 18

x² = 81

x = √81

x = 9

d)4x , 20 , 3x

(4x)² + (3x)² = 20²

16x² + 9x² = 400

25x² = 400

x² = 400/25

x² = 16

x = √16

x = 4

e)( 2x )² = x² + ( 3 √3)²⇒ 4x² = x² + 9 . 3 ⇒   4x² - x² = 27

3x² = 27

x² = 27 / 3

x²= 9  

x = √ 9  

x=3

f)  x+5 , x+3 , 6

(x+5)² = (x+3)² + 6²

x² + 10x + 25 = x² + 6x + 9 + 36

x² + 10x - x² - 6x = 9 + 36 - 25

4x = 20

x = 20/4

x = 5