Question

calcule o valor de x nos triângulos

Answer 1

a) $h^{2} = c^{2} + c^{2}$
 
$h^{2} = 6^{2} + 8^{2}$

$h^{2} = 36+ 64 h^{2} = 100 h= \sqrt{100} h= 10$


b) 

$h^{2} = c^{2} + c^{2} h^{2} = 9^{2} + 12^{2} h^{2} = 81 + 144 = 225 h= \sqrt{225} = 15$


c)
$h^{2}= c^{2} + c^{2} 5^{2} = 4^{2} + c^{2} 25 = 16 + c^{2} 25-16 = c^{2} c^{2} = 9 c= \sqrt{9} = 3$
   

As respostas finais  é a resposta de x