Question

calcule o valor de X nos triângulos

Answer 1

A)
Hip²= a²+ b²
(2x)² = X² + (3√3)²
4X²= X² + 9√9
4X²-X²= 9 × 3
3X² = 27
X²= 27/3
X²= 9
X= √9
X= 3

B)
Hip²= a² +b²
(X + 5)² = (X + 3)² + (6)²
X² + 10X + 25 = (X² + 6X + 9) + 36
X² + 10X + 25 = X² + 6X + 45
(X²- X²) + (10X - 6X) + (25 - 45) = 0
0 + 4X - 20 = 0
4X = 20
X = 20/4
X = 5