Question

Calcule o valor de x nos seguintes triângulos retângulos

Answer 1

Resposta:

Explicação passo a passo:

a) x= 8

$x^{2}$+$6^{2}$=$10^{2}$

$x^{2}$+36=100

$x^{2}$= 100-36

$x^{2}$= 64

x= 8

b )x= $\sqrt{5}$

$\sqrt{2} ^{2}$+$\sqrt{3} ^{2}$= $x^{2}$

2+3= $x^{2}$

$x^{2}$= 5

x= $\sqrt{5}$

c) x=3

   $x^{2}$+$6^{2}$= $3\sqrt{5} ^{2}$

$x^{2}$+36= 9 . 5

$x^{2}$+36= 45

$x^{2}$= 45-36

$x^{2}$= 9

x= 3

d) x= 9

$x^{2}$+$3\sqrt{2} ^{2}$= $3\sqrt{11} ^{2}$

$x^{2}$+ 9 . 2 = 9 . 11

$x^{2}$ + 18= 99

$x^{2}$= 99-18

$x^{2}$= 81

x= 9