Question

Calcule o valor de x no triângulo retângulo abaixo:

Answer 1

${h}^{2} = {a}^{2} + {b}^{2} \\ {10}^{2} = {x}^{2} + ( \frac{3x}{4} )^{2} \\ 100 = {x}^{2} + \frac{9 {x}^{2} }{16} \\ 100 = \frac{16 {x}^{2} + 9 {x}^{2} }{16} \\ 100 = \frac{25 {x}^{2} }{16} \\ 25 {x}^{2} = 1600 \\ {x}^{2} = \frac{1600}{25} \\ {x}^{2} = 64 \\ x = \sqrt{64} \\ x = 8$