Question

Calcule o valor de X no triângulo retângulo:
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Answer 1

$\large\boxed{\begin{array}{lr}(3 \sqrt{5} ) {}^{2} = 6 {}^{2} + x {}^{2} \\ 45 = 36 + x {}^{2} \\ 45 - 36 = x {}^{2} \\ \sqrt{9} = \sqrt{x {}^{2} } \\ \boxed{ \red{x = 3}} \end{array}}$