Question

calcule o valor de x nks triângulos retângulos

Answer 1

Basta fazer Pitágoras:

a)
${x}^{2} = { \sqrt{2} }^{2} + { \sqrt{3} }^{2} \\ {x}^{2} = 2 + 3 \\ {x}^{2} = 5 \\ x = \sqrt{5}$

b)
${h}^{2} = {c}^{2} + {c}^{2}$
$( {3 \sqrt{5} })^{2} = {6}^{2} + {c}^{2} \\ 45 = 36 + {x}^{2} \\ {x}^{2} = 9 \\ x = \sqrt{9} \\ x = 3$
$x = 3$

Answer 2

h² = b² + c²
h = hipotenusa
b = cateto
c = cateto

a)
x = h= hipotenusa
√3 = b = cateto
√2 = c = cateto

x² = √2² + √3²
x² = 2 + 3
x² = 5
x = √5

b)
3√5 = h= hipotenusa
x = b = cateto
6 = c = cateto

(3√5)² = x² + 6²
(3²).(√5)² = x² + 36
9.5 = x² + 36
45 = x² + 36
45 - 36 = x²
x² = 9
x = √9
x = 3